Linear acceleration in a uniform magnetic field due to torque

AI Thread Summary
To determine the maximum linear acceleration of a square loop in a magnetic field, the moment of inertia must be calculated for each side of the loop about the axis of rotation. The relationship between torque, moment of inertia, and angular acceleration is given by the equation τ = Iα, where τ is torque and α is angular acceleration. The linear acceleration at the side opposite the hinge can be expressed as a = rα, indicating that it is dependent on the torque, which reaches its maximum when the magnetic field is perpendicular to the current. Understanding when the torque is maximized is crucial for solving the problem. The axis of rotation for the loop is along the hinged side.
astralboy15
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Here the extra credit question I'm stuck on:


A square loop (perimeter of 4L and hinged along one side) is made of a wire that has a mass per unit length of 0.1000 kg/m and carries a current of 5.000 A. A uniform magnetic field of 10.00 mT directed perpendicular to the hinged side exists in the region. Determine the maximum linear acceleration magnitude, (a t) max , of the side of the loop opposite the hinged side.


My Question:
My teacher gave me a hint that torque = I*alpha, where I is the moment of inertia. How do I find the moment of inertia for this box? Then how do I work with angular acceleration to get the answer I'm after?

Thanks!
 
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What is the axis of rotation of the loop.

To find out I of the loop about this axis, you will need to find out the I's for each side of the loop about the axis and sum them.

\tau = I \alpha

a = r \alpha

You can see that a depends upon the torque and it is max when the torque is max.

When is the torque max?
 
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