VinnyCee
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Given that A^2 is invertible, does it neccesarily mean that
\left(A^2\right)^{-1}\,=\,\left(A^{-1}\right)^2?
I know that this is true, but I have no idea on where to even start a proof of this!
Maybe:
\left(A^2\right)^{-1}\,=\,\left(A\,A\right)^{-1}
But how would I operate on infinite matrices (i.e. - a_{i\,j})?
\left(A^2\right)^{-1}\,=\,\left(A^{-1}\right)^2?
I know that this is true, but I have no idea on where to even start a proof of this!
Maybe:
\left(A^2\right)^{-1}\,=\,\left(A\,A\right)^{-1}
But how would I operate on infinite matrices (i.e. - a_{i\,j})?
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