Linear Algebra and systems of linear equations problem

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SUMMARY

The discussion centers on solving a system of linear equations represented by the equations ax + ay - z = 1, x - ay - az = -1, and ax - y + az = 1. The solution is determined to be (x,y,z) = (a,b,a). Participants are tasked with finding the value of a + b when a is not an integer. The equations simplify to a^2 + ab - a = 1, a - ab - a^2 = -1, and a^2 - b + a^2 = 1, leading to further analysis of the variables.

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  • Understanding of linear algebra concepts, specifically systems of linear equations.
  • Familiarity with substitution methods in solving equations.
  • Knowledge of algebraic manipulation techniques.
  • Basic proficiency in handling variables and constants in equations.
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  • Study methods for solving systems of linear equations using substitution and elimination techniques.
  • Explore the implications of non-integer solutions in linear algebra.
  • Learn about the geometric interpretation of linear equations and their solutions.
  • Investigate the use of matrices and determinants in solving linear systems.
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Students and educators in mathematics, particularly those focusing on linear algebra, as well as anyone looking to enhance their problem-solving skills in algebraic contexts.

justin_diaz
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The solution of the system
ax + ay - z = 1
x - ay - az = - 1
ax - y + az = 1

is (x,y,z) = (a,b,a). If a is not an integer, what is the value of a + b.

A) -3/2
B) -1
C) 0
D) 1/2
E) 1

Can anyone help I don't know how to approach thisOk then you get :

a^2 + ab -a = 1
a - ab - a^2 = -1
a^2 - b + a^2 = 1

I do not see how I can solve for a+ b to get an answer..
 
Last edited:
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Substitute the values for x, y, and z into your system and see what you get. Go from there.
 

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