Linear Algebra - Basis for a row space

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SUMMARY

The discussion focuses on finding a basis for the row space of the matrix A, which is defined as follows: A = [[1, 2, -1, 3], [3, 5, 2, 0], [0, 1, 2, 1], [-1, 0, -2, 7]]. The user successfully transposed the matrix and reduced it to row echelon form, confirming that each row vector of A serves as a basis for R4. This indicates that the rows of A can generate any vector in R4 through linear combinations.

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  • Understanding of linear algebra concepts, specifically row spaces and bases.
  • Familiarity with matrix operations, including transposition and row reduction.
  • Knowledge of reduced row echelon form (RREF) and its significance in linear algebra.
  • Basic comprehension of vector spaces and linear combinations.
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  • Study the properties of vector spaces and their dimensions.
  • Learn about the Gram-Schmidt process for orthonormal bases.
  • Explore applications of row spaces in solving linear systems.
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Students and professionals in mathematics, particularly those studying linear algebra, as well as educators seeking to enhance their understanding of row spaces and basis concepts.

jinksys
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A =
Code:
 1  2 -1  3
 3  5  2  0
 0  1  2  1 
-1  0 -2  7

Problem: Find a basis for the row space of A consisting of vectors that are row vector of A.

My attempt:

I transpose the matrix A and put it into reduced row echelon form. It turns out that there are leading ones in every column. Therefore, the basis includes every row vector from A.

Is this the correct way to handle this problem?
 
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Yes, that works.
 
What you found means that the rows of A form a basis for R4, meaning that every vector in R4 can be written as a linear combination of the four vectors that are the rows of A.
 

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