Linear Algebra determine the conditions

[_Bd_]

Homework Statement

determine the conditions on a b c and d such that the matrix
a b
c d
will be row equivalent to the given matrix:
1 0
0 1

and

1 0
0 0

Homework Equations

The Attempt at a Solution

I have no idea what its asking, I mean on no. 1:
a = 1 b = 0 c = 0 and d =1
but what does that mean? I tried taking the resultant

for the first one would be 1(1) - 0(0) = 1

which would be ad - bc = 1 ??

 

[Mark44]

Homework Statement

determine the conditions on a b c and d such that the matrix
a b
c d
will be row equivalent to the given matrix:
1 0
0 1

and

1 0
0 0

Homework Equations

The Attempt at a Solution

I have no idea what its asking, I mean on no. 1:
a = 1 b = 0 c = 0 and d =1
but what does that mean? I tried taking the resultant

for the first one would be 1(1) - 0(0) = 1

which would be ad - bc = 1 ??

This looks to me like two separate problems, or one problem with two parts.
Determine the conditions on a b c and d such that the matrix
a b
c d
will be row equivalent to the given matrix:
a)
1 0
0 1

b)
1 0
0 0

By "resultant" I think you mean determinant, and you're on the right track with that approach.

 

[_Bd_]

yes, they are 2 problems, and yes I meant the determinant :P
still if I am on the right approach. . .thats as far as I can go. . .is that the answer?
a)
ad - bc = 1b)
ad - bc = 0

 

[Mark44]

You should start a new thread for the other problem.

For the original problem, suppose the matrix is
[2 1]
[3 0]

Will it be row-equivalent to the identity matrix or to the other one (the one that has all zeroes except for the upper left entry)?

 

[_Bd_]

You should start a new thread for the other problem.

For the original problem, suppose the matrix is
[2 1]
[3 0]

Will it be row-equivalent to the identity matrix or to the other one (the one that has all zeroes except for the upper left entry)?

2(0) - 3(1) = -3 . . .Im guessing no? (its not zero nor 1)
or if you do some opperations
-r1 + r2 =
[1 -1]
[3 0]
and r_3 - 3r1

[1 -1]
[0 3]
divide by 3 on row 2
[1 -1]
[0 1]

add row_1 + row_2
[1 0]
[0 1]
what I don't understand is what
row equivalency is? unless it means that its like "multiples" (or row-operation-wise) of each other?

if so then what you mentioned is row equivalent to a) ??
still how would I write the answer?

 

[HallsofIvy]

Okay, now do the same that to the matrix given: actually row-reduce the given matrix!

From
\begin{bmatrix}a & b \\ c & d\end{bmatrix}
as long as a\ne 0 we can divide the first row by a, then subtract c times the first row from the second to get
\begin{bmatrix}1 & \frac{b}{a} \\ 0 & d- \frac{bc}{a}\end{bmatrix}

If d- bc/a\ne 0 (which is the same as saying det= ad- bc= 0), we have the second form. If not, we can divide the second row by that and get the first form.

If a= 0, we can swap the rows, getting
\begin{bmatrix}c & d \\ a & b\end{bmatrix}
Now what?