ok i know about the thing, i think its called gauss-jordan, where you do elimination on [A I] and you get [I A^-1] or [R E]or something like that.(adsbygoogle = window.adsbygoogle || []).push({});

question is how can you get the E that puts A into reduced row echelon form with "row operations" only...supposedly some easy way ?

on pg 134 Gilbert Strangs book "introduction to linear algebra" he says:

"EA = R

The square matrix E is the product of elementary matrices Eij and Pij and D^-1...." yea thats all he says about doing that, but it was good enough to get it on the exam, and probably the final now lol

on pg 139 he does some work that doesn't look like steps but he gets two differant E that can get A unto rref... so whats the secret? :P

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# Linear algebra EA=R factorization question

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