Linear Algebra Help: Calculating Eigenvalues & Eigenvectors of Matrix A

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To calculate the eigenvalues and eigenvectors of the given matrix A, row-reduction can be used to transform the matrix into upper-triangular form, which simplifies the process. The discussion emphasizes that the determinant itself is a single value and does not need to be made triangular. Reordering the rows can facilitate easier row-reduction, and the optimal order may vary depending on the eigenvalue being analyzed. For finding eigenvectors, it is suggested to apply this row-reduction method for each eigenvalue. This approach will streamline the calculation of both eigenvalues and eigenvectors effectively.
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Homework Statement



Calculate the eigenvalues and eigenvectors of the matrix:
$$ A= \begin{bmatrix}
3 & 2 & 2 &-4 \\
2 & 3 & 2 &-1 \\
1 & 1 & 2 &-1 \\
2 & 2 & 2 &-1
\end{bmatrix} $$

Homework Equations



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The Attempt at a Solution



I've found the eigenvalues, but what disturbes me, is that I can't find a way to make the determinant triangular, as to find the values faster. Can anybody see a way to do that?
 
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You wouldn't make the determinant triangular, the determinant is just one number.

You can make the matrix triangular by row-reduction:
- number the rows top to bottom 1-4.
- reorder the rows: 3-2-4-1 --> 1-2-3-4
- after that the row-reduction to upper-triangular form should come easily.

You probably want to do this for each eigenvalue to find the eigenvectors - so the best order for the rows will be different each time.

You want to try this for the eigenvectors - consider:
http://www.millersville.edu/~bikenaga/linear-algebra/eigenvalue/eigenvalue.html
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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