Linear Algebra - How to represent this transformation?

AI Thread Summary
The discussion focuses on determining the eigenvalues and corresponding eigenvectors of a linear operator T on R3, given specific transformations of certain vectors. To construct the matrix representation of T, it is suggested to apply T to the standard basis vectors, which involves calculating T(1,0,0), T(0,1,0), and T(0,0,1). Participants discuss using linear combinations of the given vectors to express the transformations and utilize T's linearity for evaluation. The conversation emphasizes the importance of understanding how T operates on combinations of vectors to derive the full matrix. Ultimately, the goal is to represent T as a matrix to facilitate finding eigenvalues and eigenvectors.
zeion
Messages
455
Reaction score
1

Homework Statement



Given that T is the linear operator on R3 with T(1,1,1) = (0,0,1), T(1,1,0) = (1,2,1), T(1,0,0) = (0,-1,0), determine the eigenvalues of T and a corresponding eigenvector for each eigenvalue.


Homework Equations





The Attempt at a Solution



I know how to find eigenvalues and vectors but usually the matrix is given.. I'm not sure how to represent these transformations as one whole matrix.. or do I need to do them separately?
 
Physics news on Phys.org
You can get the columns of the matrix by applying T to the basis vectors, so you just need to figure out how to calculate T(1,0,0), T(0,1,0), and T(0,0,1) to find the matrix.
 
Okay in that case I can make an augmented matrix with the given relations and row reduce the left side to be the standard basis and the augmented side will be affect of T on the standard basis? Then I can transpose that to get the matrix?
 
Last edited:
If you can find a, b, and c such that

(0,1,0) = a(1,1,1)+b(1,1,0)+c(1,0,0)

then

T(0,1,0)=T[a(1,1,1)+b(1,1,0)+c(1,0,0)]=...

Use T's linearity to evaluate the RHS. Do the same for the vector (0,0,1).
 
I don't really understand.. How can I know what T does just by looking at the vectors that T is applied to..?
 
Like I said, use the fact that T is linear to evaluate the RHS.
 
Okay so for
(0,1,0) a = 0, b= 1, c=-1
(0,0,1) a = 1, b = -1, c = 0
 

Similar threads

Replies
3
Views
2K
Replies
4
Views
3K
Replies
9
Views
8K
Replies
4
Views
2K
Replies
32
Views
2K
Replies
13
Views
2K
Replies
69
Views
8K
Back
Top