Linear Algebra: Multiplication by Special Matrices

robbie11
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Im working on this problem and got stuck i would appreciate any help...

Let Eij be the n × n matrix with 1 at the (i, j)th place and zero elsewhere.
For a scalar c in K, put S = I + cEij . And let T be the n × n
matrix obtained from the identity matrix as follows. In I replace 1 at
the (i, i)th and (j, j)th entries by zero. Replace zeros at the (i, j)th and
(j, i)th entry by 1. Suppose A is an n × n matrix. Compute SA, AS,
TA, and AT to conclude what does the multiplication on the left or
right by S or T do to the row or columns of A.

robbie
 
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Welcome to PF!

Hi robbie! Welcome to PF!: :smile:

(try using the X2 tag just above the Reply box :wink:)

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:

(if you want to write the matrices out, either use the CODE tag, 3 to the left of the X2 tag, or use LaTeX and http://www.physics.udel.edu/~dubois/lshort2e/node54.html#SECTION00830000000000000000" )
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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