Linear Algebra Proof Homework: Prove p < or = 10, Linearly Independent Columns

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SUMMARY

The discussion centers on proving that for a 2000 x 10 matrix A, if the vectors Av1, Av2, ..., Avp are linearly independent in R2000, then the number of vectors p must be less than or equal to 10. Additionally, it is established that if p equals 10, the columns of matrix A are also linearly independent. The reasoning is based on the fundamental theorem of linear algebra, which states that the maximum number of linearly independent vectors in Rn is n, thus confirming that p cannot exceed the number of columns in A.

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Homework Statement



Let A be a 2000 x 10 matrix and v1, v2, ... , vp vectors in R10. Suppose that Av1, Av2, ... , Avp are linearly independent vectors in R2000.

a) Prove that p is < or = to 10
b) Prove that if p = 10, the columns of A are linearly independent


Homework Equations



Given above

The Attempt at a Solution



At first my line of thinking was that the products Av1, Av2 etc each had 10 unknowns and that these were somehow all related so that if there were more than 10 terms of Av1, Av2, ... , Avp then the linear combination would be linearly dependent. But I think at this point I'm just confusing myself, and it's difficult for me to picture a linear combination of a linear combination... So any help would be greatly appreciated!
 
Physics news on Phys.org
If [tex]\{Av_1, \dots, Av_p\}[/tex] is linearly independent, can [tex]\{v_1, \dots, v_p\}[/tex] be linearly dependent?
 

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