Linear Algebra Proofs for A^2=0 and p(A^2)<p(A)

AI Thread Summary
The discussion focuses on proving two key points in linear algebra regarding a matrix A. First, if A^2=0, it is established that the columns of A are in the solution space of Ax=0, leading to the conclusion that the rank of A, denoted as p(A), is at least n/2. Second, it is argued that if the rank of A^2 is less than the rank of A, then the system Ax=0 has a non-trivial solution, and the system A^2x=0 has a solution y such that Ay≠0. Participants seek assistance in properly formulating these proofs in mathematical notation. The conversation emphasizes the importance of clear mathematical expression in conveying these concepts.
Anatolyz
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Hello !
i try to solve Linear algebra question(but need be written properly as mathmatical proofs)
Having A matrice nXn:
1)proove that if A^2=0 the columns of matrice A are vectors in solution space of the system Ax=0 (x and 0 are vectors of course),and show that p(A)>=n/2
2)proove that if p(A^2)<p(A) (p in all cases here means: the rank of the vectors)
so the system Ax=o has a non trivial solution and the System A^2x=0 has solution y which is Ay≠0,,,,
I have the general clue but how write it right,math way i have big problem..
thank you very much
 
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Anatolyz said:
Hello !
i try to solve Linear algebra question(but need be written properly as mathmatical proofs)
Having A matrice nXn:
1)proove that if A^2=0 the columns of matrice A are vectors in solution space of the system Ax=0 (x and 0 are vectors of course),and show that p(A)>=n/2
What is A(1, 0, 0...)T? A(0, 1, 0,...)T?, etc.

2)proove that if p(A^2)<p(A) (p in all cases here means: the rank of the vectors)
vectors don't have "ranks". I presume you mean the rank of A2 and A.

so the system Ax=o has a non trivial solution and the System A^2x=0 has solution y which is Ay≠0,,,,
I have the general clue but how write it right,math way i have big problem..
thank you very much
If you have a "general clue" please tell us what it is. Perhaps we can help with the mathematics notation for that. I started to give a hint but I suspect it may be just your "general clue".
 
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