Linear algebra proofs (linear equations/inverses)

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Homework Help Overview

The discussion revolves around two problems in linear algebra concerning homogeneous systems of linear equations and the properties of a specific matrix. The first problem asks for a proof regarding the equivalence of two homogeneous systems with the same solutions. The second problem involves proving the invertibility of a given matrix and the nature of its inverse.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore the definition of equivalent systems of linear equations and question whether the original poster's assertion about equivalence is accurate. There is also discussion about the conditions for a matrix to be invertible, particularly focusing on the determinant.

Discussion Status

The discussion is ongoing, with participants questioning assumptions and definitions related to the problems. Some guidance has been offered regarding the nature of equivalent systems and the conditions for matrix invertibility, but no consensus has been reached on the proofs themselves.

Contextual Notes

There is a noted ambiguity regarding the definition of equivalent systems, and participants are considering the implications of the matrix's dimensions in relation to its invertibility. The original poster expresses uncertainty about how to approach the problems.

yankans
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Homework Statement



Two problems.
(1) Prove that if two homogeneous systems of linear equations in two unknowns have the same solutions, then they are equivalent.

(2) Can you prove that the matrix
A = [1 1/2 ... 1/n
1/2 1/3 ...1/(n+1)
...
1/n 1/(n+1)...1/(2n-1)]
is invertible and that A^(-1) has integer entries?

Homework Equations


(1) Perhaps the theorem - Equivalent systems of linear equations have the same solutions? It is the other way round.

(2)hmm...I don't know of "relevant equations"

The Attempt at a Solution


Not very sure how to start. For the first one, tried to construct arbitrary matrices A and B to represent two different homogeneous systems, but didn't get very far.
For (2), tried row-reducing the matrix > echelons but don't know how a proof will result...
 
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I think #1 is false, actually, unless they mean row-equivalent.
 
yankans said:

Homework Statement



Two problems.
(1) Prove that if two homogeneous systems of linear equations in two unknowns have the same solutions, then they are equivalent.

(2) Can you prove that the matrix
A = [1 1/2 ... 1/n
1/2 1/3 ...1/(n+1)
...
1/n 1/(n+1)...1/(2n-1)]
is invertible and that A^(-1) has integer entries?

Homework Equations


(1) Perhaps the theorem - Equivalent systems of linear equations have the same solutions? It is the other way round.
What is the definition of "equivalent systems"?

(2)hmm...I don't know of "relevant equations"
A matrix is invertible if and only if its determinant is not 0.

The Attempt at a Solution


Not very sure how to start. For the first one, tried to construct arbitrary matrices A and B to represent two different homogeneous systems, but didn't get very far.
For (2), tried row-reducing the matrix > echelons but don't know how a proof will result...
 
HallsofIvy said:
What is the definition of "equivalent systems"?


A matrix is invertible if and only if its determinant is not 0.

The question mentions nothing about square matrices specifically.
 
Scigatt said:
The question mentions nothing about square matrices specifically.
? It says:
A = [1 1/2 ... 1/n
1/2 1/3 ...1/(n+1)
...
1/n 1/(n+1)...1/(2n-1)]

Since it has n rows and n columns, that's pretty square!
 
HallsofIvy said:
? It says:
A = [1 1/2 ... 1/n
1/2 1/3 ...1/(n+1)
...
1/n 1/(n+1)...1/(2n-1)]

Since it has n rows and n columns, that's pretty square!

I was talking about the first part only.
 
The question (1) wants you to prove equivalence in that all the equations in each system are linear combinations of the equations in the other system (I guess that B_11*x_1 + B_12*x_2 +...B_1n*x_n = (c_1*A_11+...+c_m*A_m1)x_1 +(c_1*A_12+...+c_m*A_m2)x_1 +...(c_n*A_1n+...+c_m*A_mn)x_1 = 0).
 

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