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Linear Equations

  1. May 31, 2010 #1
    1. The problem statement, all variables and given/known data
    Find the equation of the plane that passes through the line of intersection of the planes 4x - 3y - z - 1 = 0 and 2x + 4y + z - 5 = 0 and parallel to the x - axis.

    2. Relevant equations

    3. The attempt at a solution
    The equation of the plane: 4x+2kx-3y+k4y-z+kz-1-k5=0

    do i then assume the plane parallel to the x-axis has points (1,0,0)?

    then sub into the equation and solved k=-2

    therefore the equation will be =-11y+3z-9?
  2. jcsd
  3. Jun 1, 2010 #2
  4. Jun 1, 2010 #3
    Assuming your first general equation of the planes is correct, then this method is correct. However one minor point: It sounds as though you never really showed that 0=-11y+3z-9 is parallel to the x-axis, but this is pretty trivial (you showed that if a plane of the desired form exists and that is parallel to the x-axis, then it must be this, but what if no plane of the desired form exists that is parallel to the x-axis?).
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