Linear Independence: Determining w/ Wronskian Matrix

dashkin111
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Homework Statement


Using the wronskian (determinant basically), determine if e^x, sin(x), cos(x) are linearly independent



Homework Equations


I used this:
<br /> | e^{x} sin(x) \:cos(x)|
<br /> |e^{x} cos(x) -sin(x)|
|e^{x} -sin(x) -cos(x)|

But pretend that's just a 3x3 matrix and you take the determinant of it



The Attempt at a Solution



After finding the determinant I get -2e^x which is never 0 so they're linearly independent. Am I right in this?
 
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Yes, but you know the wronskian only has to be nonvanishing someplace for the functions to be linearly independent, right?
 
Dick said:
Yes, but you know the wronskian only has to be nonvanishing someplace for the functions to be linearly independent, right?

Oh wow, I thought it was at all points. If possible, would you mind telling me why that is?
 
Sure. If f1(x), f2(x) and f3(x) are linearly dependent, then there are nonzero constants such that c1*f1(x)+c2*f2(x)+c3*f3(x) is identically zero over some interval. So a linear combination of columns in your matrix is zero. This tells you det=0 over the interval. So if det is non-zero anywhere, you know they aren't linearly dependent.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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