Linear Systems (differential equations)

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Homework Statement



I don't have a homework question. I have more of a general question.

Let's say we have a solution...

x=C1*[a1 a2]^{T}*e^{lamda1*t} + C2*[b1 b2]^{T}*e^{lamda2*t}

As t approaches infinity how do you determine what the solution does?

Homework Equations





The Attempt at a Solution



My guess is that a1,a2,b1,b2 don't matter.

If lamda1>0,lamda2>0 , and lamda1>lamda2 then as t approaches infinity then x will look more like the first term. As t approaches negative infinity the solution will look more like the second term.

If lamda1>0 and lamda2<0 then as t approaches infinity the solution will look more like first term. When t approaches negative infinity the solution will look more like the second term.

The coefficients (C1,C2) help determine whether the solution will approach negative infinity or infinity as t approaches one or the other.

So if the dominant term has a postive lamda and a negative coefficient then the solution will approach negative infinity as t approaches infinity?

So do I have it right?

Thank you for your time.
 
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Just to clarify a few things.

T=transpose
t=variable
lamda1,lamda2,c1,c2,a1,a2,b1,b2= constants
 
It depends on whether lambda1 and lambda2 (the correct English spelling) are positive or negative.

Your solution x is the sum of two vectors. Let's look at each of them separately. If \lambda_1 > 0, then e^{\lambda_1 t} approaches infinity as t approaches infinity. This means that the first vector in the sum is growing longer as t gets large.

If \lambda_1 < 0, then e^{\lambda_1 t} approaches zero as t approaches infinity. This means that the first vector in the sum is getting shorter as t gets large.

The same kind of analysis can be done for \lambda_2, and its effect on the second vector.
 
Thank you that answers part of my question. I am trying to look at x as a whole though to see how x changes as t goes to infinity or negative infinity. I am curious if my thoughts for how the system as a whole is correct. In my first post I give a few specific examples. Were my assumptions correct?
 
What you said is mostly correct. The part that is incorrect is what you said about the solutions approaching infinity or negative infinity. The solution is a sum of two vectors, not a number.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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