Linear Transformation and Linear dependence - Proof

1nonly
Messages
1
Reaction score
0

Homework Statement


Let T:Rn to Rm be a linear transformation that maps two linearly independents vectors {u,v} into a linearly dependent set {t(u),T(v)}. Show that the equation T(x)=0 has a nontrivial solution.

Homework Equations



c1u1 + c2v2 = 0 where c1,c2 = 0

T(c1u1 + c2v2) = T(0) where c1 or c2 /= 0

The Attempt at a Solution



Since we know:

T(c1u1 + c2v2) = T(0) where c1 or c2 /= 0
T(c1u1) + T(c2v2) = T(0)
c1T(u1) + c2T(v2) = T(0)
c1T(u1) + c2T(v2) = 0 (c1 or c2 /= 0)

T(x) = 0 has trivial solution
c1T(x) = 0 where c1 /= 0

I'm not sure how to connect those two ideas or if there even relevant to the solution proof.
 
Physics news on Phys.org
I'm not sure what your last expression is supposed to mean, but the block of four equations is already the proof. Maybe it is easier to see it, if you read it backwards.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top