Verify that the given function is in the kernel of L.
L = x2D2 + 2xD - 2
The Attempt at a Solution
I took the first and 2nd derivative of y(x), and got
Then plugged it into L (and a little simplifying) and got
L(y) = 6x-2+2x-1-2
I think I'm supposed to plug it in, and verify that it's equal to zero, but it's not coming out right.
Any obvious mistakes? Or wrong direction all together?