Little help with practice problem for exam. (tension in strings)

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To solve the problem of finding the tension in the lower string supporting a steel ball, it's essential to start with a free-body diagram to visualize the forces acting on the ball. The ball is in equilibrium, meaning the sum of the forces must equal zero, which involves separating the forces into their horizontal and vertical components. The tension in the lower string can be determined by analyzing the horizontal component of the tension in the upper string, which is at an angle of 27 degrees from the vertical. Trigonometric vector analysis is recommended to create a force-vector triangle, allowing for the calculation of the necessary side lengths and angles. Understanding vector addition is crucial for correctly applying these principles to find the tension in the lower string.
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Hello, I'm new here. Basically I have this practice excercise for my exam.:

A steel ball of mass 4.30 kg is suspended from two strings as shown in the picture. The upper string is at an angle of theta = 27.0° from the vertical, while the lower string is horizontal. Calculate the magnitude of T2, the tension in the lower string.


http://capa.hep.uprm.edu/msuphysicslib/Graphics/Gtype06/prob09_xph183f6pic2.gif

My general problem is that I'm bad with separating forces into components, and I assume this excercise deals with that. Can someone please point me in the right direction to solving this problem? Any help will be greatly appreciated.
 
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Always begin these types of problems with a free-body diagram (draw each force vector acting on the object). Remember that since the object is in equilibrium, all the force vectors, when added vectorally, should give zero. Use that and the angle and mass given, and you should be able to solve this.
 
Ok i believe that in order to get the tension in the horizontal string, I I need to get the horizontal component of the upper string since the lower string doesn't have a vertical component.

But the angle they give me is kinda weird.

I tried setting the tension in the lower string ewual to m*g*cos(27) but that does not give me the correct answer...
 
In this case, doing trigonometric vector analysis is easier. Use vector addition to create a force-vector triangle, then use trigonometry (should be easy once you have the right triangle).
 
... :rolleyes: You lost me on the last one.
 
Sorry. Have you learned how to do vector addition and analysis? Draw all the vectors for the forces present, then place them tip to tail, and fill in angle and magnitude values, which gives you a right-angle triangle (in this case) with two side lengths and an angle, meaning you can find all the other info.
 
Ok I did this but what are the side lengths? The angle is the 90deg one right?
 

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