- #1
AbsoluteZer0
- 125
- 1
Hello all,
Am I right in assuming that [itex]log(\frac{3}{5}) = \frac{log3}{log5}[/itex]?
Thanks,
Am I right in assuming that [itex]log(\frac{3}{5}) = \frac{log3}{log5}[/itex]?
Thanks,
AbsoluteZer0 said:Hello all,
Am I right in assuming that [itex]log(\frac{3}{5}) = \frac{log3}{log5}[/itex]?
Thanks,
A logarithm is a mathematical function that is the inverse of exponentiation. It is used to solve equations involving exponents and to convert between different forms of exponential equations.
To solve a logarithmic equation, you can use the properties of logarithms to simplify the equation and then apply the inverse operation of logarithms, which is exponentiation, to both sides of the equation.
The base of a logarithm is the number that is raised to a certain power to get the argument of the logarithm. For example, in the logarithm log2(8), 2 is the base.
Yes, the base of a logarithm can be any positive number except 1. However, the most commonly used bases are 10, e (Euler's number), and 2. Different bases result in different values for the logarithm of the same number.
Yes, this is one of the properties of logarithms, known as the quotient rule. It states that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and denominator. So, log(a/b) = log(a) - log(b).