Lorentz Transformation of Vectors from S to S' Frame

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Homework Help Overview

The discussion revolves around the Lorentz transformation of 4-vectors, specifically focusing on the transformation of a photon's 4-momentum from one inertial frame (S) to another (S'). The original poster presents the problem of relating the 4-momentum of a photon in the S frame to its counterpart in the S' frame, which is moving at a velocity v in the positive x direction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the Lorentz boost using a gamma factor to relate the 4-momentum P to P' in the S' frame. They also inquire about the transformation of frequency f to f' and suggest a similar approach. Some participants provide insights on using a Lorentz boost matrix for the transformation, emphasizing the need to express the 4-momentum as a column vector.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on using the Lorentz boost matrix to transform the 4-momentum. The original poster is seeking clarification on the matrix multiplication process and how to proceed with the calculations. There is an ongoing exploration of the relationships between the components of the 4-momentum and the frequency transformation.

Contextual Notes

The discussion includes considerations about the nature of the photon’s 4-momentum being light-like and the implications of the relationship between energy and momentum in the context of special relativity. The original poster expresses uncertainty about the correctness of their attempts and seeks further assistance.

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Homework Statement



The question is quite basic; what is the Lorentz transformation of the follows 4-vectors from S to S' frame:

A photon (P) in S frame with 4-momentum

P = (E/c,p,0,0) and

frequency f where

hf = pc = E. h is the planks constant, p is the magnitude of 3-momentum and E is energy.

S' frame travels in positive x direction with position v speed (ie. not an ANTIPARTICLE).

...so how's P' related to P? P' is momentum in S' frame

My attempt:

Lorentz boost, simple gamma factor (sqrt (1-(v/c)^2)) relationship with P to give a P' answer as

P' = √(1-(v/c)^) * P

Correct?

How above the relationship of f and f'? f' is the frequency of photon in S' frame.

My attempt:

Same as above, gamma relationship with f to give

f' = √(1-(v/c)^) * f

Correct?

Thanks everyone
 
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You have to write the 4-momentum as a column vector
##\begin{bmatrix}E/c\\p\\0\\0\end{bmatrix}##
and operate on it with the Lorentz boost matrix, which is
##\Lambda=\begin{bmatrix}\gamma&-\beta\gamma&0&0\\-\beta\gamma&\gamma&0&0\\0&0&1&0\\0&0&0&1\end{bmatrix}##
for boosts in the ##x##-direction. Here ##\beta=v/c##, where ##v## is the relative velocity of the frames. Then you get the components of the four-momentum in the new frame. The frequency changes in the transformation by the same factor as the energy component of the 4-momentum vector.
 
Last edited:
In addition note that for a photon the four-momentum is
(p^{\mu})=\begin{pmatrix}<br /> |\vec{p}| \\ \vec{p},<br /> \end{pmatrix}
because a photon's four-momentum is light-like.
 
hilbert2 said:
You have to write the 4-momentum as a column vector
##\begin{bmatrix}E/c\\p\\0\\0\end{bmatrix}##
and operate on it with the Lorentz boost matrix, which is
##\Lambda=\begin{bmatrix}\gamma&-\beta\gamma&0&0\\-\beta\gamma&\gamma&0&0\\0&0&1&0\\0&0&0&1\end{bmatrix}##
for boosts in the ##x##-direction. Here , where ##v## is the relative velocity of the frames. Then you get the components of the four-momentum in the new frame. The frequency changes in the transformation by the same factor as the energy component of the 4-momentum vector.

Hi,

Thank you for replying (hilbert and vanhees!). I cross multiply the matrix, factor in the fact that E=pc to get:

γP * matrix

[ 1, -v/c]
[-v/c, 1 ]

How do I solve this?
 

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