Lorentz transformation Problem, Confused on setting it up

sealsix14
Messages
2
Reaction score
0
So this is my first course in upper level physics, and I'm still trying to figure out special relativity.

The problem:

Two events occur at the same place in a certain inertial frame and are separated by a time interval of 4sec. What is the spatial separation between these two events in an inertial frame in which the events are separated by a time interval of 6 sec?

I know the problem states that the two events occur in a certain inertial frame (frame S), and have a dt = 4. but I'm confused as to what It is exactly asking, is it asking what the d would be in another inertial frame where the dt = 6? I'm Just confused on setting up the problem and feel stupid.
 
Physics news on Phys.org
I'm always rusty with this stuff too. SR is the hardest thing, don't believe people if they tell you otherwise ;) I would think that the total spacetime interval in both frames has to be the same, that is (\Delta s)^2 is the same in all frames. so let's use
<br /> (\Delta s)^2 = (\Delta t)^2 - (\Delta \vec{x})^2<br />
In the first frame we know that
<br /> (\Delta s)^2 = (4)^2\<br />
since there is no spatial change. But in the other frame it is
<br /> (\Delta s)^2 = (6)^2 - (\Delta \vec{x})^2<br />
Now the kicker is that (\Delta s)^2 is the same for both frames. The question is then, what does (\Delta \vec{x})^2 have to be to make that true? I hope this helps/is right.
 
This problem seems to be designed to give you a little experience in applying the Lorentz Transformation. In addition to the method that jfy4 described, you can also solve this directly by using the Lorentz Transformation. Let's say that the two events occur in the S frame of reference. According to the problem description, what is the difference in spatial positions between the two events (Δ x) and what is the difference in times of the two events (Δt)? Now, from the Lorentz Transformation, what are the corresponding quantities (Δx') and (Δt') for the S' frame of reference (expressed in terms of the relativity factor γ and v/c)? Since the problem statement already tells you what Δt' is in the S' frame of reference(6 sec), you can use one of the LT equations to solve for γ, and then v/c. You can then substitute into the other equation to get Δx'. The result you get should match what jfy4's method gives.
 
Thanks, I'll give this a try and see If I get anywhere with it.
 
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Does the speed of light change in a gravitational field depending on whether the direction of travel is parallel to the field, or perpendicular to the field? And is it the same in both directions at each orientation? This question could be answered experimentally to some degree of accuracy. Experiment design: Place two identical clocks A and B on the circumference of a wheel at opposite ends of the diameter of length L. The wheel is positioned upright, i.e., perpendicular to the ground...
According to the General Theory of Relativity, time does not pass on a black hole, which means that processes they don't work either. As the object becomes heavier, the speed of matter falling on it for an observer on Earth will first increase, and then slow down, due to the effect of time dilation. And then it will stop altogether. As a result, we will not get a black hole, since the critical mass will not be reached. Although the object will continue to attract matter, it will not be a...

Similar threads

Back
Top