Lorentz Transformation Rapidity

parsikoo
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Concerning Rapidity, if tanh(Fi) = v/c, can it be concluded in general that the relative angle of two frames in combination with Lorentz Transformation is tan(theta) = tanh(Fi) = v/c, where theta is the relative angle?
 
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What do you mean by the "relative angle"?
 
Yes,
\theta_{21} = \theta_{20}-\theta_{10}.
 
Fredrik said:
What do you mean by the "relative angle"?

I meants relative angle of the frames.
 
parsikoo said:
I meants relative angle of the frames.
That's what you said but what does it mean?
 
Simply the math connection between rapidity and the angle of two frames, not sure if this is clear?
 

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