Lost with a Problem? Solve 3x-8/x^2-5x+6+x+2

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The discussion revolves around a mathematical expression, 3x-8/x^2-5x+6+x+2, which lacks an equals sign, making it unsolvable as presented. Participants emphasize the need for a clearer problem statement to provide meaningful assistance. The original poster attempts to solve for x but arrives at various incorrect answers, indicating confusion in their calculations. Key points of confusion include the manipulation of polynomial expressions and the absence of a defined equation. Clarifying the problem is essential for receiving appropriate help.
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Homework Statement



What I have is 3x-8/x^2-5x+6+x+2



Homework Equations

Haven't come upon any as of yet...



The Attempt at a Solution

My attempt was solve for x, but as I was solving I tried doing each part differently and I came out with 1.5 as an answer. So here are my steps...

3x-8: Don't know what happened, but my answer was -5.

x^2-5x+6+x+2: Here is where more confusion arises... What I did was try and solve the x variables again; add x^2 to -5x, and my outcome was 5x+x^2, then I subtracted x from 5x+x^2 and the outcome was 5x+x^2-x, from there I ended up with -4.

x^2-6x+8: Here I did basically the same as the second part and ended up with -2.

.625, and -1.5 are my answers so far... And, I am lost now and in need of support.
 
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You need to state your problem better. You don't have an = sign, so there's nothing to solve.
 
like christian said, you first need to restate your problem, so we would know what what to deal with. You cannot solve that equation unless ther is an "=" sign.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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