Luminol and synthesis (mechanism of the reaction)

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The synthesis of luminol involves a condensation reaction between 3-nitrophthalic acid and hydrazine, resulting in 5-nitrophthalhydrazide and sodium sulfate. The mechanism begins with the lone pair on hydrazine attacking the carboxylic carbon, followed by a proton transfer from hydrazine to the carboxylic -OH group. This leads to the removal of a water molecule and the formation of an amide bond. The process is repeated for the second carboxylic acid group using the remaining amine group on hydrazine. The discussion raises questions about whether both nitrogen atoms of hydrazine react simultaneously, with a consensus leaning towards the likelihood of sequential reactions.
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[SOLVED] Luminol and synthesis (mechanism of the reaction)

In lab I synthesized luminol and I'm trying to figure out the mechanism of the reaction.

3-nitrophthalic acid + hydrazine => 5-nitrophthalhydrazide + Na2SO4=> Luminol

http://spot.pcc.edu/~gbackes/ORGANIC/CH%20243/Synthesis.of.Luminol.htm

I know that the reaction is a condensation reaction in the first step but I am not sure how the reaction happens. (do the 2 sides of the molecule attack the hydrazine and then water falls off or does something else happen?)

I looked up the reaction online but the mechanism is not shown. The just say "condensation reaction" and I do notice that the water is missing and the 2 molecules end up joined but as to

who attacks who and then how does the water leave??

Thanks
 
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Roughly put,
1) Lone pair on hydrazine attacks carboxylic carbon
2) Proton transfers from hydrazine to carboxylic -OH
3) Condensation: one water molecule (i.e., protonated hydroxyl) removed (& formation of amide bond)
4) Repeat steps 1-3 for the other carboxylic acid group, with the remaining -NH2 group on hydrazine
 
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bomba923 said:
Roughly put,
1) Lone pair on hydrazine attacks carboxylic carbon
2) Proton transfers from hydrazine to carboxylic -OH
3) Condensation: one water molecule (i.e., protonated hydroxyl) removed (& formation of amide bond)
4) Repeat steps 1-3 for the other carboxylic acid group, with the remaining -NH2 group on hydrazine

Does the reaction happen with both sides at the same time? (both N's of the hydrazine?)
 
I doubt it,
though it is possible for some statistically minute quantity of 3-nitrophthalic acid to react exactly as such
 
bomba923 said:
I doubt it,
though it is possible for some statistically minute quantity of 3-nitrophthalic acid to react exactly as such

Oh, so would that other nitrogen just hang there then? until it reacted that is.
 
Most likely :)
 
bomba923 said:
Most likely :)

Thank you for your assistance with my question. :smile:
 
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