Luminol and synthesis (mechanism of the reaction)

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Discussion Overview

The discussion centers around the synthesis of luminol, specifically focusing on the mechanism of the reaction involving 3-nitrophthalic acid and hydrazine. Participants explore the details of the condensation reaction and the steps involved in the formation of luminol.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant describes the reaction mechanism in broad terms, suggesting that the lone pair on hydrazine attacks the carboxylic carbon, followed by a proton transfer and the removal of water to form an amide bond.
  • Another participant questions whether the reaction occurs simultaneously on both sides of the hydrazine molecule, seeking clarification on the mechanism.
  • Some participants express skepticism about the simultaneous reaction of both nitrogen atoms in hydrazine, suggesting it may only happen in a statistically minute quantity.
  • There is a suggestion that if one nitrogen atom reacts, the other might remain unreacted until a later stage.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether both nitrogen atoms of hydrazine react simultaneously. There are competing views on the likelihood of this occurring, with some expressing doubt and others suggesting it is possible.

Contextual Notes

The discussion includes assumptions about the reaction mechanism that are not fully resolved, particularly regarding the timing and conditions under which both nitrogen atoms may react.

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[SOLVED] Luminol and synthesis (mechanism of the reaction)

In lab I synthesized luminol and I'm trying to figure out the mechanism of the reaction.

3-nitrophthalic acid + hydrazine => 5-nitrophthalhydrazide + Na2SO4=> Luminol

http://spot.pcc.edu/~gbackes/ORGANIC/CH%20243/Synthesis.of.Luminol.htm

I know that the reaction is a condensation reaction in the first step but I am not sure how the reaction happens. (do the 2 sides of the molecule attack the hydrazine and then water falls off or does something else happen?)

I looked up the reaction online but the mechanism is not shown. The just say "condensation reaction" and I do notice that the water is missing and the 2 molecules end up joined but as to

who attacks who and then how does the water leave??

Thanks
 
Last edited by a moderator:
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Roughly put,
1) Lone pair on hydrazine attacks carboxylic carbon
2) Proton transfers from hydrazine to carboxylic -OH
3) Condensation: one water molecule (i.e., protonated hydroxyl) removed (& formation of amide bond)
4) Repeat steps 1-3 for the other carboxylic acid group, with the remaining -NH2 group on hydrazine
 
Last edited:
bomba923 said:
Roughly put,
1) Lone pair on hydrazine attacks carboxylic carbon
2) Proton transfers from hydrazine to carboxylic -OH
3) Condensation: one water molecule (i.e., protonated hydroxyl) removed (& formation of amide bond)
4) Repeat steps 1-3 for the other carboxylic acid group, with the remaining -NH2 group on hydrazine

Does the reaction happen with both sides at the same time? (both N's of the hydrazine?)
 
I doubt it,
though it is possible for some statistically minute quantity of 3-nitrophthalic acid to react exactly as such
 
bomba923 said:
I doubt it,
though it is possible for some statistically minute quantity of 3-nitrophthalic acid to react exactly as such

Oh, so would that other nitrogen just hang there then? until it reacted that is.
 
Most likely :)
 
bomba923 said:
Most likely :)

Thank you for your assistance with my question. :smile:
 

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