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(M1 x 1)+(M2 x2) / M1+M2

  1. Jul 1, 2010 #1
    Particle A is at the origin and has a mass of 32.2 g. Particle B has a mass of 10.0 g. Where must particle B be located if the coordinates of the center of mass are (x, y) = (2.0 cm, 5.5 cm)?


    (M1 x 1)+(M2 x2) / M1+M2

    I have worked this out so many times and continue to get the wrong answer. Heres what I have:


    solving for Xb =
    (32.2 x 0) + (10.0 x 2.0) / 32.2 + 10.0 = 2.57 cm can anyone help me, I dont know if Im setting up the equation wrong or if my calculations are just wrong but the answers keeps getting denied online.
     
  2. jcsd
  3. Jul 2, 2010 #2

    Uku

    User Avatar

    Hoi!

    Where did you get this from?

    [tex](M1 x 1)+(M2 x2) / M1+M2[/tex]

    I'm thinking you should consider the following:

    [tex]x_{c}=\frac{\sum m_{i}x_{i}}{M}[/tex]

    [tex]y_{c}=\frac{\sum m_{i}y_{i}}{M}[/tex]
     
  4. Jul 2, 2010 #3
    You took the wrong value.
    We don't know xb and yb

    We know centre of mass where is it. x(bar) (or) xc=2, y(bar) or yc=5.5

    Use xc=(m1x1+m2x2)/(m1+m2) . You can find x2.
    yc formular is similar as xc. You can find y2.
     
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