Where is Particle B Located in Relation to the Center of Mass?

[dnjwilson]

Particle A is at the origin and has a mass of 32.2 g. Particle B has a mass of 10.0 g. Where must particle B be located if the coordinates of the center of mass are (x, y) = (2.0 cm, 5.5 cm)?


(M1 x 1)+(M2 x2) / M1+M2

I have worked this out so many times and continue to get the wrong answer. Heres what I have:


solving for Xb =
(32.2 x 0) + (10.0 x 2.0) / 32.2 + 10.0 = 2.57 cm can anyone help me, I don't know if I am setting up the equation wrong or if my calculations are just wrong but the answers keeps getting denied online.

 

[Uku]

Hoi!

Where did you get this from?

$$(M1 x 1)+(M2 x2) / M1+M2$$

I'm thinking you should consider the following:

$$x_{c}=\frac{\sum m_{i}x_{i}}{M}$$

$$y_{c}=\frac{\sum m_{i}y_{i}}{M}$$

 

[inky]

You took the wrong value.
We don't know x_b and y_b

We know centre of mass where is it. x(bar) (or) x_c=2, y(bar) or y_c=5.5

Use x_c=(m₁x₁+m₂x₂)/(m₁+m₂) . You can find x₂.
y_c formula is similar as x_c. You can find y₂.