Mach Value64: Calculate Jet Speed after 41s at 12ms2

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To calculate the Mach value of a jet accelerating from rest at 12 m/s² for 41 seconds at a temperature of 12 degrees Celsius, the correct approach involves using the formula for velocity based on acceleration and time. The speed of sound at 12 degrees Celsius is approximately 339.08 m/s. After determining the final velocity of the jet, the Mach number can be calculated using the formula Mach# = velocity/speed of sound. It's important to ensure that all units are correctly applied, particularly for acceleration. The discussion emphasizes the need for clarity in problem statements and accurate calculations.
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Homework Statement


If the temperature is 12 degrees and a jet accelerates at rest at 12ms2 for 41s, then what is the Mach value for the jet at the end of 41 seconds


Homework Equations


mach#=vovs
speed of sound equation

The Attempt at a Solution



v=12degrees
a=12ms2
v=339,08ms
m#=vo/vs
 
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soulja101 said:

Homework Statement


If the temperature is 12 degrees and a jet accelerates at rest at 12ms2 for 41s, then what is the Mach value for the jet at the end of 41 seconds


Homework Equations


mach#=vovs
speed of sound equation

The Attempt at a Solution



v=12degrees
a=12ms2
v=339,08ms
m#=vo/vs

Your statement of the problem has numerous flaws. I assume the jet accelerates from rest, and that you meant "t=12degrees" above. Careful also to use acceleration units of meters per second^2, not m-s^2. Finally your value for v is incorrect.

What is the equation giving velocity in terms of acceleration and time? Once you have that you'll need the speed of sound at 12 degrees to finish the problem...
 
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