Magnetic energy of charged particle?

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When a charged particle at rest is given an impulse in a direction perpendicular to a uniform magnetic field, it begins to move in a circular path, resembling a current-carrying coil. The magnetic moment generated by this motion is expressed as M=I*A, and it interacts with the magnetic field, contributing to the system's energy. The discussion raises questions about conservation of energy, specifically how the kinetic energy from the impulse relates to the magnetic energy generated. It is argued that the energy associated with the magnetic moment does not add to the kinetic energy but instead represents a different manifestation of the same energy. This perspective emphasizes the interconnectedness of kinetic and magnetic energies in such a system.
quawa99
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Consider a situation where you have a charge at rest in a uniform magnetic field.A sharp impulse is given to the charge in a direction perpendicular to the magnetic field,if the velocity is high enough the charge which starts revolving in circular path should behave like a current carrying coil.Now we know that a current carrying coil has a magnetic moment 'M=I*A',and we also know that this magnetic moment will give an energy to it which is equal to 'M.B'.My question is what happens to conservation of energy in this case because the work done by impulsive force only gives it kinetic energy but you have another magnetic field interaction energy as mention above.
 
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The energy of the magnetic moment is not in addition to the kinetic energy, but rather another way of expressing the same energy.
 
Khashishi said:
The energy of the magnetic moment is not in addition to the kinetic energy, but rather another way of expressing the same energy.

Can you please justify your statement?
 

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