Magnetic Field and Voltage in a Conductive Tape: The Hall Effect

AI Thread Summary
A discussion on calculating voltage across a copper tape in a magnetic field highlights the use of the Hall Effect. The user attempts to apply the equation U = dBS/dt to find the voltage, expecting a result of 7.4 microV, but struggles to achieve this due to confusion over the correct application of the formula. Despite providing their calculations, they express uncertainty about the validity of their results. Participants emphasize the importance of showing all attempts to help clarify the misunderstanding. The conversation underscores the need for a better understanding of the Hall Effect and its relevant equations.
iverse
Messages
4
Reaction score
0
Puting a 150 micro.m tick coper tape into a magnetic fild of 0.65. The current going through the tape = 23 A. What is the voltage on the edges of that tape ?

Homework Equations


I used this equation: U = dBS/dt
and then - > (B*r^2*pi*I)/e_0

The Attempt at a Solution


Resoult should be 7.4 microV
 
Physics news on Phys.org
Just showing what the result should be is not enough; please show us what attempts you have made to obtain that result. We can't help you if we can't see what you have tried.
 
PeterDonis said:
Just showing what the result should be is not enough; please show us what attempts you have made to obtain that result. We can't help you if we can't see what you have tried.
What do you mean ? The resoult is not mine is from the book. Its what it should be not what i get. From the equation i put up i get totaly difrent stuff i don't even think its the right one. I hope someone can resolve this...
 
PeterDonis said:
Just showing what the result should be is not enough; please show us what attempts you have made to obtain that result. We can't help you if we can't see what you have tried.
Sorry * hmm i didn t even see it said the attempt :P. Its the actual resoult as i said.
 
iverse said:
Its what it should be not what i get.

So what do you get and how do you get it?
 
PeterDonis said:
So what do you get and how do you get it?
I use the equation that i wrote. The resoult is really irelevant cus it must be wrong but here it is.

B= 0.65 r = 0.75 * 10^-6 and I = 23 so -> (0.65 * (0.75*10^-6)^2 * pi * 23) / (1.6 * 10^-19) = 1.65 * 10^8 is what i get
 
Where did your Relevant equations come from, and what is their area of application? The information in your problem statement doesn't seem to pertain to the variables in those equations.

Hint: Look up "The Hall Effect".
 
Back
Top