Magnetic field around charging capacitor

AI Thread Summary
The discussion focuses on calculating the magnetic field between two circular capacitor plates connected to a current. Using Ampere's Law, the user seeks to find the magnetic field as a function of radial distance (r) while considering the displacement current due to the changing electric field as the capacitor charges. The user acknowledges that the electric field (E) is uniform between the plates and seeks clarification on how to express E as a function of time. The relationship between electric flux and the changing electric field is emphasized, with the user attempting to derive the necessary equations for their problem. Overall, the conversation revolves around applying theoretical concepts to solve a practical physics problem.
chronokinetic
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Hi everyone, I'm doing a problem that involves two circular capacitor plates with radius R connected to wires running current I (as in a circuit), and need to find the magnetic field at three different regions between the two plates as a function of r, radial distance from the center of the two plates.

Using Ampere's Law, ∫B*dl = μ(I +εd\Psi/dt)

where μ and ε are the magnetic constant and electric constant.
B is magnetic field, I is current, and \Psi is flux of electric field (between the two cap. plates, I 'spose).

I figured the best loop to integrate over is a circle (parallel to and in between the two plates).

How will I go about it from here?
 
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If those plates are parallel, That exact problem is an example in my (old) edition of Halliday and Resnick PHYSICS FOR STUDENTS OF SCIENCE AND ENGINEERING

E is constant between the plates, neglecting fringe effects.
 
Thanks, I know the E is uniform, but how can you find B as a function of r ("r"adial distance away from center of plates)?
 
@chronokinetic: The current is charging the capacitor, therefore there is a change in the E field of the capacitor. How will that affect the displacement current?
 
what is the displacement current? I don't know what it is.
As current I charges capacitor q, the e field should change, meaning the electric flux through a circle between the plates also increase. There is no current between the plates so I=0, but there is d\Psi/dt, so ampere's law is:

∫B*dl = \mu*d\Psi/dt

Electric flux \Psi = ∫E dA = E2\pir
d\Psi/dt = ?

How do I get E as a function of time? The distance between the plates is small so E can be written with q, A, and \epsilon according to the problem. I know I = dq/dt

E for point change is E=kQ/r2

Am I doing it right?
 
It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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