Magnetic Field inside plate

AI Thread Summary
The discussion focuses on calculating the magnetic field inside and outside a large, flat conducting plate with a linearly decreasing current density described by J = J0(1-az). The solution for the magnetic field outside the plate is confirmed as B = (μ0 J0)/(4a), matching the textbook answer. However, the user struggles with the calculation for the magnetic field inside the plate, where their derived expression does not align with the book's solution, which includes an additional term, 1/(4a). The user seeks clarification on how to correctly account for the magnetic fields above and below the plate to resolve this discrepancy. The conversation emphasizes the importance of properly applying Ampere's Law in this context.
deedsy
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Homework Statement


What is the magnetic field outside and inside of a large, flat conducting plate if the current density decreases linearly with depth z inside the plate. J = J0(1-az). The plate thickness is 1/a.

Homework Equations


*see below

The Attempt at a Solution


\oint \vec B \cdot d \vec l = \mu_0 I

So outside the plate,
2Bl = \mu_0 \int J_0(1-az)ldz *The integral is taken from from z=0 to z=1/a (the whole plate)
B=\frac{\mu_0 J_0}{4a}

Which agrees with the back of the book solution.

Now inside is where I am having trouble...
I tried applying Ampere's Law again but I just got
\oint \vec B \cdot d \vec l = \mu_0 I
2Bl = \mu_0 \int J_0(1-az)ldz *taking the integral from 0 to z this time
B=\frac{\mu_o J_0}{2} (z-\frac{az^2}{2})

but the back of the book says the answer is B = \mu_0 J_0 (\frac{az^2}{2} - z +\frac{1}{4a})

So I'm not sure where the \frac{1}{4a} came from... Does anyone know how i should go about finding the magnetic field inside the plate?
 
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At some point z, you have a field above and a field below. You should account for both of them.
 
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Got it - thanks for the help
 
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