- #1

Hiero

- 322

- 68

$$\frac{\mu_0 q \vec v \times \vec r}{4\pi r^3}$$

but when I calculate it by transforming the electrostatic field (taking the motion along x) I get,

$$\frac{\gamma \mu_0 q \vec v \times \vec r}{4\pi ((\gamma x)^2+y^2+z^2)^{3/2}}$$

I can't find anything like this version anywhere. I just want to confirm that the version I keep seeing online is just the low speed limit where the gamma factor is approximately one? Or am I wrong?