B How Does Proton Spin Influence Its Magnetic Field?

Javier Lopez
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I do not understand the theory of moment of nuclei

I read here: http://www.sjsu.edu/faculty/watkins/nuclearmoment3.htm that the magnetic moment of Hydrogen is 2.79284734 magnetons = 2.79284734*9.274009994e-24 joules/tesla =2.59e-23 joules/tesla
So if I make to rotate a proton using 150 keV could I have a magnetic field at the proton surface accordingly following expresion?
$$\frac{150keV*1.6022*10^{-16}\frac{Joule}{keV}} {2.59*10{-23}\frac{Joules}{tesla}}=928 megateslas$$

Do I have to multiply with some constants?
Is the magnetic momento of a proton = 0?
 
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You would need such a huge external field to make the two proton spin orientations differ in energy by 150 keV.
+- some numerical prefactors maybe.
 
You are right, not only difficult for 2 hydrogens but almost impossible due heating over some eV they may get divorced :).

Single protons that have almost the same moment: 2.7928473508 but I suppose may be impossible align all ions due temperature makes them go free pointing anywere and the magnetic field is shielded by external ions and electrons.

I do not know about how is proton internal structure, but seems to be like a charged bump on surface rotating to create a loop that generates a magnetic dipole

Where mathematics prefactors can be found?, I have not bibliography of "atom spin and momentum" or a sample exercise about that and I have to include calculus in a small excel sheet that I am making
 
Javier Lopez said:
I do not know about how is proton internal structure, but seems to be like a charged bump on surface rotating to create a loop that generates a magnetic dipole
No, the magnetic moment is purely from spin of the proton.

Experimentally we cannot rule out a contribution from an electric dipole moment but it has to be tiny.
https://arxiv.org/abs/1502.04317
Javier Lopez said:
Where mathematics prefactors can be found?
If in doubt: In textbooks.
 
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