Magnetic field produced at point P

AI Thread Summary
The discussion revolves around deriving the magnetic field at point P due to a current-carrying wire, specifically addressing a discrepancy between the calculated direction of the magnetic field and the answer provided in the textbook. The participant derives a formula and concludes that the magnetic field should point into the page, while the textbook claims it points out of the page. They express confusion over this contradiction, particularly when applying the right-hand rule. Other participants agree that the outer arc contributes a weaker field directed out of the page, while straight segments contribute no field. The participant plans to consult their instructor for clarification on the issue.
Rijad Hadzic
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Homework Statement


https://imgur.com/gallery/vCOZq

Its question 26, and the figure can be seen at figure 30.26

Derive and expression for the magnetic field produced at point P due to the current carrying wire shown in figure 30.26. The curved parts of the wire are pieces of concentric circles. Point P is at the center.

Homework Equations



b = \mu IR^2 / (2)(R^2 +y^2)^{3/2}

The Attempt at a Solution



Ok so in the above eq setting y = 0, I get

b = - (\Theta /2pi) * ( \mu I /2R_1 )
(\Theta /2pi) because we are only looking at a portion (\Theta /2pi) of a circle.
for the wire closest to the point P.

I say the magnetic field is going INSIDE the page at point p, which means -z axis, but my book is telling me the field is out of the page.

Is my book wrong here? I don't see how, using the simple right hand rule, the field could possibly be pointing out of the page.
 
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Rijad Hadzic said:
I don't see how, using the simple right hand rule, the field could possibly be pointing out of the page.
I don't see it either. The outer arc generates a field that is out of the page that is weaker because its radius is larger. The straight segments, of course, generate no field at point P.
 
kuruman said:
I don't see it either. The outer arc generates a field that is out of the page that is weaker because its radius is larger. The straight segments, of course, generate no field at point P.
Yup. And this answer is coming from the instructors manual for this book. Such a shame. Maybe someone will find the trick? (if there is one?)
 
Rijad Hadzic said:
Yup. And this answer is coming from the instructors manual for this book. Such a shame. Maybe someone will find the trick? (if there is one?)
You may wish to take your solution to your instructor and ask what's going on.
 
kuruman said:
You may wish to take your solution to your instructor and ask what's going on.
Yup that's what I'm going to have to do...
 
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