Magnetic field produced by a current

AI Thread Summary
The discussion focuses on calculating the magnetic flux density produced by a single-loop coil with a radius of 30mm and a current of 5 amps. The user reports experimental results of 6.2 mV at a distance of 10mm, which do not match theoretical predictions based on the formula β = μ0*I*n/2πr. Participants highlight the importance of using correct units and address potential errors due to environmental factors, such as not being in a vacuum. There is confusion regarding the calculations, particularly the placement of values in the equation and the significance of the voltage measurement in relation to the magnetic field. The conversation emphasizes the need for clarity in problem presentation and accurate unit conversions for successful calculations.
carl binney
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Homework Statement


IMG_1081.JPG
this is the equation for flux density we have been given, the radius 30mm, z= goes in stages of 10mm, from zero to 50mm, then from zero to -50mm. that symbol at the begin of equation is 4 pie ! and the current is 5 amps. its is for a single-loop coil

Homework Equations

The Attempt at a Solution


I have tried the equation and the answer is nothing like my experimental results. which is 6.2 mV, at 10mm.
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One of the basic formulas I've learned is that that magnet flux density can be expressed as:
β = μ0*I*n/2πr
Where μ0 is the permeability vacu vacuum, n as the numbers of the turn of the coil and r is the distance to the coil :)
 
thanks, but i missed something out the question, the equation is for single-loop coil
 
Yep, that's the equation for singlz loops,
Eitherway you've got 0.003 voltage difference and unfortunately these things happens due to many errors, one of them is that we're not living in the vacuum, :)
 
Hello Carl, welcome to PF :smile: !

Please read the guidelines . You get better help if you present a clear and concise problem.
What is this about ?
What are the relevant equations ?

Apparently you are measuring something in terms of mV.
What does that have to do with the magnetic field B ?

Also your calculations should be typed (or better: typeset). But your picture does come through clearly. Pity you don't have ##r^2## in the numerator, and it's totally unclear to me why you have ##30^2## and not ##(10^{-3})^2## in the denominator. Also, the ##10^2## should be ##(10\times 10^{-3})^2##
 
thanks again, I might seem stupid, I have only done physics since Christmas , I can't see how there is only a 0.003 voltage difference ?
 
Oh, and ##\mu_0 = 4\pi \times 10^{-7}## N/A2, not just ##4\pi##.
 
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hi thanks for the advice every one, 0.01 is in the equation because the first measurement of the magnetic field was measured 10 mm away from the centre of the single loop coil, is this equation correct ?
 
I get that too. Now check that you get the right units.
 
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