Magnetic Force of a Right Triangle influenced by a Line

AI Thread Summary
To calculate the magnetic force on a right triangle influenced by a line, the magnetic field must be considered as non-constant, requiring integration. The equation B = u0*I/2piR is used for the magnetic field, while F = iLB applies to the bottom side of the triangle. For the other two sides, the magnetic field can be integrated, but the relationship between the variables R and L needs clarification. Using the midpoint of the sides to represent the entire line is only valid if the magnetic field varies linearly with distance. Setting up an integral is essential for accurate calculations.
g85108
Messages
1
Reaction score
0

Homework Statement

http://www.sumoware.com/images/temp/xzlknterambqmokp.png

How to calculate the Magnetic Force of THE "Right Triangle" influenced by a Line
when the magnetic field isn't constant B=u0*I/2piR?

Homework Equations


B=u0*I/2piR
F=iLB

The Attempt at a Solution


I can use F=iLB to calculate the bottom line.
But how to calculate the two other sides magnetic field.
How to integral the magnetic field?
Is it possible to use the middle point of the two sides to represent the whole line?
 
Last edited by a moderator:
Physics news on Phys.org
F=∫IXB dL

Consider you can compute the integral once you figure out how to connect the two variables R and L
 
g85108 said:
Is it possible to use the middle point of the two sides to represent the whole line?

That would work only if the magnetic field varied linearly with distance from the wire at the bottom, e.g. B = kr. I think you need to set up an integral, as throneoo noted.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Does levitation distance increase as Fg increase???
Replies
1
Views
873
Understanding work in translation and rotation of a magnetic dipole
Replies
1
Views
2K
Force between poles of two magnets
Replies
1
Views
1K
(Magnetism) Magnetic pull force on a steel ball
Replies
4
Views
2K
Determine the force with which the magnetic field of a coil acts on an infinitesimal cube of iron
Replies
6
Views
917
What is the net force on the current loop?
Replies
8
Views
2K
Tangent Angles for Lines of Force, Two Equal Positive Charges
Replies
29
Views
1K
What is the induced magnetic force on this closed current loop?
Replies
12
Views
2K
How does an eddy current brake work exactly?
Replies
2
Views
2K
Magnetization of a paramagnetic sphere
Replies
11
Views
1K

Hot Threads

Recent Insights

Back
Top