Magnetic Force on High Voltage Power Line: Calculate Direction & Magnitude

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The discussion focuses on calculating the magnetic force on a high voltage power line carrying a current of 110 A in the presence of the Earth's magnetic field, which has a magnitude of 0.59 G directed 72 degrees below the horizontal. The formula used for the calculation is F = ILB SinX, where the user attempts to find the force for two scenarios: current flowing east and south. The user expresses uncertainty about their calculations and suggests breaking the magnetic field into components due to the angle not being directly between the current and magnetic field. Clarification is sought on whether the initial calculation is correct and how to properly account for the magnetic field's angle. The discussion emphasizes the need for accurate vector analysis in magnetic force calculations.
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Homework Statement



A high voltage power line carries a current of 110 A at a location where the Earth's magnetic field has a magnitude of .59 G and points to the north, 72 degrees below the horizontal. find the direction and magnitude of the magnetic force exerted on a 250-m lengh of wire if the current in the wire flows (A) horizontally toward the east (B) horizontally toward the south.

Homework Equations



F= ILB SinX

The Attempt at a Solution


I= 110A B= .59 x 10^(-4) L=250

F= (110)(250)(.59 x 10^(-4))(sin -72)
F= -1.543
Is it correct or not! i need to know the answer. can someone please help me.
 
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I think you should break the magnetic field into components becasue 72 degree is not the angle between ILXB.
 
how should i break it down?
 

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