Magnetic Forces acting upon a slider on rails

AI Thread Summary
The discussion centers on calculating the acceleration of a metal slider on frictionless conducting rails under the influence of a magnetic field. Given a magnetic field strength of 3.0T and a current of 5.0A, the force on the current-carrying conductor is determined using the formula F = BIl, where the length of the conductor is 0.1m. This results in a force of 1.5N, leading to an acceleration of 3.75m/s² when divided by the mass of 0.40kg. The direction of the acceleration can be determined using Fleming's left-hand rule, indicating whether it moves towards or away from the battery. The key takeaway is that the slider does experience acceleration due to the magnetic force acting on it.
Peto
Messages
9
Reaction score
0
A 0.40kg metal slider is sitting on smooth (frictionless) conducting rails as shown below. What is the magnitude and direction of the acceleration of the slider?
Magnetic Fields.jpg

Given,

B = 3.0T I = 5.0A m = 0.40kg
R = either 0.1m or 0.05m, I am not sure if you half it because its a raidius.

How can you figure out the acceleration of the slider?
or would the acceleration be zero since the rail with the current hading left would counteract the rail with the current heading right? therefore acceleration = 0 and magnitude would not be applicable?

I'm not sure what to do here
thanks in advance for any help!
 
Physics news on Phys.org
What is the expression of the force on the current carrying conductor in a magnetic field?
0.1 m is the distance between the rails. It is also the length of the conductor sliding on the rails.
 
rl.bhat said:
What is the expression of the force on the current carrying conductor in a magnetic field?
0.1 m is the distance between the rails. It is also the length of the conductor sliding on the rails.

The expression is F=BIl
so F=(3.0T)(5.0A)(1.0m)= 15N.
Then using F=ma the acceleration would be
a=F/m=(15N)/(0.40kg)=37.5m/s^2
so if that is the acceleration, then Which way would it accelerate? Towards the battery or away?
 
Sorry the length is 0.1m so that would give a force of 1.5N and an acceleration iof 1.5/0.4=3.75m/s^2
in which direction ?
 
Use Flemming's left hand rule to find the direction of the force.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top