Magnetic Forces and Magnetic Field

AI Thread Summary
A charged particle with a charge-to-mass ratio of 5.7x10^8 C/Kg moves in a circular path within a magnetic field of 0.72 T. The discussion revolves around calculating the time it takes for the particle to complete one revolution. Participants share formulas related to magnetic forces and centripetal force, ultimately deriving the relationship between charge, mass, and radius. The correct answer for the time taken to complete one revolution is found to be approximately 1.53 x 10^8 seconds. The thread concludes with gratitude for the assistance received in solving the problem.
aesura
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Homework Statement



A charged particle with a charge-to-mass ratio of |q| / m = 5.7x10^8 C/Kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.72 T.

How much time does it take for the particle to complete one revolution?

Homework Equations



errrr.. I have no clue where to start with

The Attempt at a Solution



:( :(

Thank you for your help...
 
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*bump*

i tried to work it tho...not like I am just posting a new thread HEY GUYS COULD U PLEASE DO THIS FOR ME??

the trouble I am having is that I can't link t with all my magnetic formulas... and I've never heard of charge mass ratio...

i tried to work out hte velocity but... not enough data for it...

anyway physicists we need you!
 
Fm=qvB
Fc=(mv2)/r
because the particle is moving on a circular path,
so Fm=Fc
rearrange the formula to q/m=?, then solve for the radius
then use the radius to find the circumference,
d/t=v
where d is the circumference
Hope that helps
 
Last edited:
hmmm yea :( indeed... damn it... sorry I am med student not a physicist...

that was easy... :*( :*(

F = q v b sin 90
F = qvb

F = mv^2 / r ... obviously since a = v^2/r since it is a centri. force...

qvb = mv^2/r
q/m = v^2/rB
5.7x10^8 C/Kg = v/rB since v must be 2pi... :(


5.7x10^8 C/Kg x r = 2pi/0.72T

r = 1.53 x10^8 s

thank you so much... this is the correct answer... thanks heaps :)
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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