Magnetic susceptibility and relative permeability

AI Thread Summary
The discussion centers on deriving the relationship between magnetic susceptibility (χm) and relative permeability (μr) using the equation χm = μr - 1. Participants share relevant equations, including M = χmH and μ = μrμo, to connect magnetic properties. One user attempts various substitutions to manipulate the equations but struggles to find a clear path to the derivation. Another user provides guidance on substituting M into the equation for B, leading to a successful derivation. The conversation emphasizes the importance of using established equations to connect concepts in magnetism.
Marwa
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Homework Statement


find the derivation of
χm=μr-1
where Xm is the magnetic susceptibility and μ is the relative permeability.

Homework Equations


M=Xm.H
M is the magnetization,H is the magnetic field
μr=μ/μo
where μo is the permeability of a vacuum,


The Attempt at a Solution


I don't know how to start ,I know some equations related to magnetic properties but i cannot connect them to each other to find the derivation.
 
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Hello Marwa,

Welcome to Physics Forums! :smile:

For convenience, I've retyped in your problem.

Derive the formula,
\chi_m = \mu_r - 1

Relevant equations:
\mathrm{\textbf{M}} = \chi_m \mathrm{\textbf{H}}
\mu = \mu_r \mu_0
I'm pretty sure you will need one or two more relevant equations.
Can you find any relevant equations that relate to the magnetic field, \mathrm{\textbf{B}}?
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Relevant equations:
β=μH

βo=μoH

μr=μ/μo

β = μoH+ μoM

M=Xm.H
 
Marwa said:
Relevant equations:
β=μH

βo=μoH

μr=μ/μo

β = μoH+ μoM

M=Xm.H

Okay, with these relevant equations,
\mathrm{\textbf{M}} = \chi_m \mathrm{\textbf{H}}
\mu = \mu_r \mu_0
\mathrm{\textbf{B}} = \mu \mathrm{\textbf{H}}
\mathrm{\textbf{B}} = \mu_0 \left( \mathrm{\textbf{H}} +\mathrm{\textbf{M}} \right)
you have enough to show that
\chi_m = \mu_r - 1.
What have you tried so far?
 
I have tried :

M=Xm.H
Xm=M/H
Xm=Mμ/B
as H=B/μ
and B=μo(H+M)
Xm=(M.μ)/μo(H+M)
so Xm=μr.M/(H+M)
 
Marwa said:
I have tried :

M=Xm.H
Xm=M/H
Xm=Mμ/B
as H=B/μ
and B=μo(H+M)
Xm=(M.μ)/μo(H+M)
so Xm=μr.M/(H+M)

Try substituting
M = χmH
into
B=μ0(H+M)​
Then factor the H.
 
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I got it:

B=μo(H+M)
and M=XmH
B=μo(H+XmH)
B=μoH(1+Xm)
so μH=μoH(1+Xm)
μ/μo=μr
Xm=1-μr

Thank you.
 
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DERIVE THE RELATIONSHIP B = μ0(H + M)
 
Inusa Adamu Gurai said:
DERIVE THE RELATIONSHIP B = μ0(H + M)
I need the same,
Help me of you find it
 
  • #10
Arun said:
I need the same,
Help me of you find it
Hello @Arun,

I suggest starting a new thread if you need help on this. Be sure to use the automatic template (problem statement, relevant equations, attempted solution, and so forth).
 
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