Magnetism and Conducting Loops: Which Description is Correct?

  • Thread starter Thread starter KLscilevothma
  • Start date Start date
  • Tags Tags
    Magnetism
AI Thread Summary
The discussion centers around a physics exam question regarding the behavior of a conducting loop in the presence of a bar magnet. The key points include the interaction of the loop with the magnetic field, where the loop experiences forces due to induced currents. The correct answer options are debated, particularly focusing on whether the loop is attracted or repelled and how its area changes. It is clarified that if the loop is flexible, the opposing currents in different segments cause repulsion, leading to an increase in the loop's area as it expands. The confusion arises around the concept of area versus volume expansion, with participants emphasizing that the loop's sides will stretch, thereby increasing the area, rather than merely expanding in volume.
KLscilevothma
Messages
315
Reaction score
0
This question appeared in the physics exam yesterday and I'm not sure what is the correct answer.

The figure shows a light and flexible conducting loop C freely hung on a smooth horizontal rail. A bar magnet PQ approaches the loop from the right. Which of the following descriptions about this process is correct ?
A. if P is an N-pole, the loop will be repelled ot the left and its area will increase slightly.
B. If P is an N-ple, the loop will be attracted to the right and its area will decrease slightly.
C. No matter whether P is an N-pole or a S-pole, the loop will be repelled to the left and its are will decrease slightly.
D. No matter whether P is an N-pole or a S-pole, the loop will be repelled to the left and its area will increase slightly.

I think the correct answer is either C or D but I don't know why the change in area of the loop is involved in this process.

Edit:typo
 

Attachments

  • a.bmp
    a.bmp
    14.5 KB · Views: 547
Last edited:
Physics news on Phys.org
Originally posted by KLscilevothma
I think the correct answer is either C or D but I don't know why the change in area of the loop is involved in this process.
Think of two current-carrying wires side by side. They exert forces on each other, depending on the orientation of the currents. Now consider that loop with its induced current. Segments of the loop on opposite sides carry current in opposite directions, so they repel each other. So the flexible loop expands.
 
Um.. but what I can imagine is volume expansion of the loop but the area doesn't change, just like the case when 2 current carring wires are put side by side, they repel each other if the currect direction is opposite. Am I missing something here ?
 
Originally posted by KLscilevothma
Um.. but what I can imagine is volume expansion of the loop but the area doesn't change, just like the case when 2 current carring wires are put side by side, they repel each other if the currect direction is opposite. Am I missing something here ?
I don't know what you mean by "volume" expansion of the loop. If two current-carrying wires repel, they will spread apart if free to do so. For the loop, opposite sides repel. Since the loop is flexible, the sides will stretch open, increasing the loop area.
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top