- #1
Offlinedoctor
- 12
- 0
Hi I'm currently reading up on magnetism and its relation to currents but there's one thing that frustrates me and the textbook doesn't seem to elaborate on it.
I understand that a current produces its own magnetic field (and we use the right-hand rule to determine this), it also makes sense that if we throw a particle into this current-created field, we can measure the force it feels via F = qvB. What's frustrating me is that in the next section, the textbook outlines how if we place a current-carrying wire on a magnetic field, the wire will feel a force of F = i.l.b.sin(x), but before it says that a current produces a magnetic field, so won't the magnetic field it produce partially cancel out the external magnetic field?
I understand that a current produces its own magnetic field (and we use the right-hand rule to determine this), it also makes sense that if we throw a particle into this current-created field, we can measure the force it feels via F = qvB. What's frustrating me is that in the next section, the textbook outlines how if we place a current-carrying wire on a magnetic field, the wire will feel a force of F = i.l.b.sin(x), but before it says that a current produces a magnetic field, so won't the magnetic field it produce partially cancel out the external magnetic field?
