Magnetoelectric induction, I think

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The discussion revolves around a homework problem involving magnetoelectric induction, where the student is tasked with calculating the total voltage at two voltmeters connected in a circuit. The configuration's nature—whether it is an electromagnetic coil or two separate circuits—is unclear, raising questions about the application of Faraday's Law. The student is uncertain about the angle 'theta' in the magnetic flux equation and how to incorporate the time-varying nature of the magnetic field, given its sine wave characteristics. The known parameters include a radius of 0.1m, a magnetic flux density of 100 Teslas, and a frequency of 1000 kHz. Clarification on these points is essential for solving the problem accurately.
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Homework Statement



All I've been given concerning this problem is the diagram below and the instruction to solve for the total voltage at both voltmeters.

Unfortunately, I am not sure whether this configuration counts as a electromagnetic coil, or whether it is simply two single-wire circuits, one for each voltmeter, connected at Points A and B. It also isn't clear from the diagram whether voltmeter #1, and its associated circuit, is in the same plane as the other voltmeter.

The known data:
radius = .1m (A = .01pi)
magnetic flux density = 100w/m^2 or 100 Teslas
frequency = 1000 kHz

Homework Equations



I have been assuming that this each circuit is a coil (with one turn) and that I can use Faraday's Law: EMF = dphi/dt

where phi = the magnetic flux = B*A*cos(theta)

The Attempt at a Solution



Quite frankly, I'm stuck. I'm not sure what 'theta' represents. B*A = 100w/m^2*.01m^2*pi = pi webers, so flux = pi * cos(theta). Is theta the angle of the coil? And once I get phi, how to I use Faraday's Law?
 

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I am not sure about the diagram, but since they say that the magnetic field is a sine wave, the magnetic field B must vary with time. Write B as a function of time.
 
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