Magnetoelectric induction, I think

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SUMMARY

The discussion focuses on solving for the total voltage at two voltmeters in a configuration involving magnetoelectric induction. The known parameters include a radius of 0.1m, a magnetic flux density of 100 W/m² (100 Teslas), and a frequency of 1000 kHz. The participant is applying Faraday's Law, specifically EMF = dφ/dt, where φ represents the magnetic flux calculated as B*A*cos(θ). Clarification is needed regarding the angle θ and the time-varying nature of the magnetic field.

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Homework Statement



All I've been given concerning this problem is the diagram below and the instruction to solve for the total voltage at both voltmeters.

Unfortunately, I am not sure whether this configuration counts as a electromagnetic coil, or whether it is simply two single-wire circuits, one for each voltmeter, connected at Points A and B. It also isn't clear from the diagram whether voltmeter #1, and its associated circuit, is in the same plane as the other voltmeter.

The known data:
radius = .1m (A = .01pi)
magnetic flux density = 100w/m^2 or 100 Teslas
frequency = 1000 kHz

Homework Equations



I have been assuming that this each circuit is a coil (with one turn) and that I can use Faraday's Law: EMF = dphi/dt

where phi = the magnetic flux = B*A*cos(theta)

The Attempt at a Solution



Quite frankly, I'm stuck. I'm not sure what 'theta' represents. B*A = 100w/m^2*.01m^2*pi = pi webers, so flux = pi * cos(theta). Is theta the angle of the coil? And once I get phi, how to I use Faraday's Law?
 

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I am not sure about the diagram, but since they say that the magnetic field is a sine wave, the magnetic field B must vary with time. Write B as a function of time.
 

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