Magnitude and angle of the displacement vector

AI Thread Summary
The discussion revolves around calculating the magnitude and angle of the displacement vector for the minute hand of a clock during specific time intervals. Participants express confusion regarding the correct interpretation of angles, particularly the need to measure counterclockwise from the positive x-axis. For the interval from 2:15 to 2:30, the angle should be 270 degrees, not 90 degrees, as the latter is measured clockwise. Clarification is sought on how to approach the problem and confirm the correct angle measurements. The conversation highlights the importance of understanding the direction of angle measurement in physics problems.
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Homework Statement



The minute hand of a wall clock measures 14 cm from its tip to the axis about which it rotates. The magnitude and angle of the displacement vector of the tip are to be determined for three time intervals. What are the (a) magnitude and (b) angle from a quarter after the hour to half past, the (c) magnitude and (d) angle for the next half hour, and the (e) magnitude and (f) angle for the hour after that? Give all angles as positive values measured counterclockwise from the +x direction (to the right, or 3 o'clock).

Homework Equations


The Attempt at a Solution



I have no idea how to approach this problem. I am confused on the wording of part B..Help anyone?
 
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well it means that 2:15 to 2:30, you want the angle made from going from 2:15 to 2:30 by the hand
 


so wouldn't that angle be 90 degrees? I put that, but It was not correct.
 


tjbateh said:
so wouldn't that angle be 90 degrees? I put that, but It was not correct.

that is 90 degrees measuring clockwise, the question said to measure counter-clockwise from the +ve x direction.
 


so 270?
 


tjbateh said:
so 270?

that is what it looks like it should be
 


hmmm..
 
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