Magnitude of the maximum gravitational force

In summary, the first question involves calculating the maximum gravitational force between two uniform spheres using the formula F=Gm1m2/r^2, where G is the gravitational constant, m1 and m2 are the masses of the spheres, and r is the distance between their centers. The second question involves finding the maximum acceleration that an airplane can have without a cup of coffee sliding backward on a table, which can be determined by setting the frictional force equal to the product of the coefficient of static friction and the weight of the cup and solving for acceleration using the formula F=ma.
  • #1
iceT
8
0
Hello all..I need some help on these 2 questions..:rolleyes:
Thanx


-A bowling ball (mass = 7.2 kg, radius = 0.15 m) and a billiard ball (mass = 0.47 kg, radius = 0.028 m) may each be treated as uniform spheres. What is the magnitude of the maximum gravitational force that each can exert on the other?

I know its the gravitational force ...so is it going to be this way?..

F= G m1m2/r^2 ...where G= 6.673x10^-11 N :confused:
?:confused:




-A cup of coffee is sitting on a table in an airplane that is flying at a constant altitude and a constant velocity. The coefficient of static friction between the cup and the table is 0.20. Suddenly, the plane accelerates, its altitude remaining constant. What is the maximum acceleration that the plane can have without the cup sliding backward on the table?

for this 1 I'm totally lost...:bugeye:
 
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  • #2
The gravitational force between the balls (they will experience the same force, but in opposite directions) will be a maximum when the distance betwen the balls are a minimum.

For the cup of coffee - the frictional force on the cup will accelerate it in the direction of the plane's acceleration.
 
  • #3
Yes, that is the formula for gravitational force. r is the distance between their centers. What is the distance between the two centers when the balls are touching?

The maximum possible force on the cup before it starts to slide is 0.2 times the weight of the cup= 0.20mg where m is the mass of the cup. Also, F= ma. Solve for a.
 

FAQ: Magnitude of the maximum gravitational force

1. What is the magnitude of the maximum gravitational force?

The magnitude of the maximum gravitational force is the greatest amount of force that can be exerted between two objects due to their mass and distance from each other.

2. How is the magnitude of the maximum gravitational force calculated?

The magnitude of the maximum gravitational force can be calculated using the formula F = G(m1m2)/r^2, where F is the force, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between them.

3. Does the magnitude of the maximum gravitational force change with distance?

Yes, the magnitude of the maximum gravitational force decreases as the distance between two objects increases. This is known as the inverse square law, which states that the force is inversely proportional to the square of the distance between the objects.

4. How does the mass of the objects affect the magnitude of the maximum gravitational force?

The magnitude of the maximum gravitational force increases as the masses of the objects increase. This means that the force between two objects with larger masses will be greater than the force between two objects with smaller masses, given the same distance between them.

5. Can the magnitude of the maximum gravitational force ever be negative?

No, the magnitude of the maximum gravitational force is always a positive value. This is because the force of gravity is always attractive and never repulsive, meaning that it always pulls objects towards each other.

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