Make x the subject of the equation.

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To make x the subject of the equation sin(5x-24)=0.6, the steps involve isolating the term: 5x-24=arcsin(0.6). This leads to the equation 5x=24+arcsin(0.6), which simplifies to x=(24+arcsin(0.6))/5. The approximate value of x is 12.174, or about 4.93 if measured in radians. It is noted that there are infinitely many solutions due to the periodic nature of the sine function, but the arcsin function's range is limited to [-π/2, π/2].
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Homework Statement



Make x the subject of the formula

sin(5x-24)=0.6

Homework Equations



sin(5x-24)=0.6

The Attempt at a Solution



sin(5x-24)=0.6
5x-24=sin^-1(0.6)
x=(sin^-1(0.6)+24)/5
 
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You had it right I believe, what exactly is your question?

sin(5x-24) = 0.6

5x - 24 = arcsin(0.6)

5x = 24 + arcsin(0.6)

x = [24 + arcsin(0.6)] / 5

X = ~12.174
 
Or, if (5x-24) is measured in radians, x is about 4.93.
 
There should be an infinite number of solutions, shouldn't there? Remember that the range of the arcsin function is only [-π/2, π/2].
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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