Create Your Own zF Capacitor | PF

AI Thread Summary
The discussion centers on the challenge of creating a capacitor with capacitance in the zeptofarad (zF) range, which is not commercially available. Participants explore theoretical calculations for capacitance and the impracticality of achieving such small values with traditional methods, noting that self-capacitance values are context-dependent. Suggestions include using multiple small capacitors in series or exploring nanotechnology for practical solutions. The conversation also touches on the limitations of measuring and detecting such tiny capacitances, emphasizing the need for context to understand their application. Ultimately, the thread concludes with participants expressing satisfaction with the insights gained.
G Cooke
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Hi PF,

I am in need of a capacitance in the zF (zeptofarad = E-21) range.

Of course, they aren't sold this small, so I was wondering if maybe someone with more physics knowledge could help me create my own zF capacitor.

Thanks in advance!
 
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G Cooke said:
Hi PF,

I am in need of a capacitance in the zF (zeptofarad = E-21) range.

Of course, they aren't sold this small, so I was wondering if maybe someone with more physics knowledge could help me create my own zF capacitor.

Thanks in advance!
The formula to calculate capacitance is:

C = 0.224 * (n-1) * K * A / d

C in pf (10[sup}-12[/sup]
n = number of plates
K = dielectric constant (1 for air or a vacuum)
A = area of one side of one plate
d = separation between plates

That says the separation must be 0.224*109 as large as the plate area. For a plate 1 inch sq. the separation would be about 3,535 miles, a little more than the width of the North American continent. That's an awful long wire to the second plate, with its own capacitance to the environment. I suggest you try a different approach.
 
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The capacitance of a plain wire can be much higher .

The only situations that I know of where zeptoFarad levels of capacitance have any tangible meaning or significance are in the very specialised technologies of scanning capacitance microscopy and nano scale sensors .

Tom.G said:
I suggest you try a different approach
+1

Is there any actual purpose to this question ?
 
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Thanks for your replies, guys.

Actually, I meant to specify that this is a self-capacitance value I'm referring to. I wrote this really late last night, so I apologize.

I would think that if I just wanted a zF capacitance in the conventional sense, I could just connect 5000000 0.05pF capacitors in series (since they add like resistors in parallel) to get about 10zF, right? (But you couldn't conclude that the self-capacitance of one plate of this zF capacitor would necessarily be in the zF range since it is independent of the distance of separation of the plates, etc.)

I see on Wikipedia that the formula for self-capacitance of a circular disk is 8εa, which requires an area of about an angstrom to get 10zF. I'm hoping maybe there's a practical way to achieve this instead.
 
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Nidum said:
Is there any actual purpose to this question ?

Hi Nidum,

Yes, a zF self-capacitance is necessary to satisfy multiple conditions in order to make it possible to prototype a certain apparatus.
 
G Cooke said:
Yes, a zF self-capacitance is necessary to satisfy multiple conditions in order to make it possible to prototype a certain apparatus.

I'm stumped by the practical matter of how will will connect your leads to it .

A Driven Guard can reduce apparent capacitance,
but how would one even detect the charge on a 10-21 f capacitor to drive the guard? At a whole volt it's less charge than resides on a single electron.
Best electrometer amplifier i know of has a picofarad or two in its Zin , which would swamp the zetafarad . A single electron at its input would produce only about a microvolt and get lost in the picoamp of input bias current .
http://www.ti.com/lit/ds/symlink/opa128.pdfInteresting problem ... how does one detect Electron Millivolts ? and Atto-Amps?
I'm out of my league here .

http://www.tek.com/sites/tek.com/files/media/document/resources/2648 Counting Electrons1.pdf
upload_2017-5-29_12-27-39.png


Watching with interest... old jim
 
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jim hardy said:
At a whole volt it's less charge than resides on a single electron.

Actually, using the exact numbers from my calculations, the charge will be the exact charge of an electron. To be specific, 5V*32.04zF=1.602E-19C.

jim hardy said:
A Driven Guard can reduce apparent capacitance

I'll take a look into this "driven guard."

jim hardy said:
I'm stumped by the practical matter of how will will connect your leads to it .

Yes, it's interesting lol. I don't know, maybe surface mount?

jim hardy said:

That's a very interesting article. Thanks, Jim.
 
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jim hardy said:
A Driven Guard can reduce apparent capacitance
So I looked up the driven guard here:

http://www.keysight.com/upload/cmc_upload/All/2-Parametric_Measurement_Basic.pdf?&cc=US&lc=eng

and I see that it reduces effective parasitic capacitance in a triaxial cable by isolating the signal line from the shield.

This would seem not very effective in my setup since what I need is actually an object whose self-capacitance is in the zF range. Perhaps this is only possible with nanotechnology; I was just hoping maybe there were some ingenious physics trick by which I could generate an "effective" zF self-capacitance without actually making the physical size so small, maybe by using an extremely low-density conductor like conductive foam or something (trying to find info on that now).
 
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G Cooke said:
and I see that it reduces effective parasitic capacitance in a triaxial cable by isolating the signal line from the shield.

Yes, point being it surrounds the signal cable with a shielding conductor(think Faraday cage) held at same potential
so there's no incentive for current to flow through the capacitance between those two conductors.
upload_2017-5-29_16-51-20.png
 
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  • #10
A 10 zF capacitor could never be connected to a circuit so the concept of 10 zF is meaningless without context. You could make a negative capacitance, then adjust it to reduce it's own input capacitance to 10 zF. You would end up with something like a driven guard.

A single atom might have about 10 zF capacitance relative to almost nothing nearby in a vacuum.

G Cooke said:
To be specific, 5V*32.04zF=1.602E-19C.
You could simulate a 32 zF capacitor with an LED. When one electron flows the voltage drop would need to be 5 V. The LED would produce a photon with a wavelength of 1240 / 5V = 248. nm which is UVC, in the middle of the UV part of the spectrum. The voltage on the UVC LED would rise by 5V when it received a 248 nm photon.

This thread should be closed if you cannot explain the context in which a 10 zF capacitor might be connected or interfaced.
 
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  • #11
Baluncore said:
This thread should be closed if you cannot explain the context in which a 10 zF capacitor might be connected or interfaced.

+1
 
  • #12
Baluncore said:
This thread should be closed if you cannot explain the context in which a 10 zF capacitor might be connected or interfaced.
Agreed. Finger hovering over mouse button... :smile:
 
  • #13
Second the motion
 
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  • #15
Baluncore said:
The LED would produce a photon with a wavelength of 1240 / 5V = 248. nm

Interesting. Could you explain where the 1240 came from?

I appreciate the many interesting facts and useful suggestions you've provided.
 
  • #16
G Cooke said:
Interesting. Could you explain where the 1240 came from?
The defined speed of light; c = 299792458. metre/second.
The absolute permeability; Uo = 4×10-7 * Pi henry/metre.
Absolute permittivity; Eo = 1 / ( Uo * c * c ) farad/metre.
The Planck–Einstein relation gives photon energy E from wave frequency; E = h * f.
Where h = Plank's constant = 6.626070040×10-34 J·s = 4.135667662×10-15 eV·s
Converting also between frequency and wavelength in nanometres uses the constant = h * c * 109 = 1239.841973862093 = 1240.
So for an LED that produces radiation of nm wavelength; voltage = eV = 1240 / nm.
 
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  • #17
berkeman said:
Agreed. Finger hovering over mouse button... :smile:
Ok, you can close it now. I got what I needed out of it.
 
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