Making a piecewise function continuous

AI Thread Summary
To make the piecewise function continuous across all intervals, the limits at x=0 and x=2 must match. The limit as x approaches 0 from the left is determined to be 2, which means the right-hand limit at x=0 must also equal 2. The values of b and c can be derived from the equations at x=0 and x=2 to ensure continuity. The discussion emphasizes the need to set conditions on b and c based on these limits. Understanding these relationships is crucial for solving the problem effectively.
meaganjulie
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Homework Statement



find the values of b and c that make the function f continuous on (-\infty,\infty)

f(x) = \frac{sin2x}{x} if x< 0
3-3c+b(x+1) if 0\leqx<2
5-cx+bx^2 if x\geq 2

Homework Equations



lim as x \rightarrow 0- of \frac{sin2x}{x}
works out to be 0

The Attempt at a Solution

 
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Welcome to PF!

Hi meaganjulie! Welcome to PF! :wink:
meaganjulie said:
lim as x \rightarrow 0- of \frac{sin2x}{x}
works out to be 0

Nope :redface:

what makes you think that? :smile:
 
nevermind, that limit is actually 2. the limit for zero from the right also must equal 2, and the right and left limits at x=2 must also match.

thats all I've got.
 
Just figure out what c and b values make the first and second equal at x=0.

The other one follows a similar process.
 
i don't understand how to find the values for c and b because i don't understand how i can use the point x=0 because the first part of the function has no c or b values. i have to use the last to equations at x=2, but how do i know what that limit is?
 
Hi meaganjulie! :smile:

(just got up :zzz: …)
meaganjulie said:
i don't understand how to find the values for c and b because i don't understand how i can use the point x=0 because the first part of the function has no c or b values. i have to use the last to equations at x=2, but how do i know what that limit is?

The first equation tells you that the limit at x = 0 must be 2.

The second equation tells you conditions on b and c which agree with that limit (at x = 0), and that gives you a formula (in b and c) for the limit at x = 2.

And the third equation tells you conditions on b and c which agree with that limit at x = 2.
 
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