Delta Typo in Photon Propagator?

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The problem is on pages 323 and 324 of the second edition.

Homework Statement


Given the lagrangian
\mathcal{L} = -\frac{1}{4}F_{\mu\nu}(x)F^{\mu\nu}(x) - \frac{1}{2\alpha}(\partial_{\mu}A^{\mu})^2
show that the momentum space photon propoagator is given by
D_F^{\mu\nu}(k) = \frac{-g^{\mu\nu} + \delta k^{\mu}k^{\nu}/k^2}{k^2 + i\epsilon}

Homework Equations


\delta = 1 - \alpha^{-1}

The Attempt at a Solution


I can solve this problem if I set
\delta = 1 - \alpha
but not with the delta stated in the book.

My question is this:

Should the book say \delta = 1 - \alpha and not \delta = 1 - \alpha^{-1}?

This question and this question only. The meat of the answer will be one word.
 
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Yes, the text is a typo. It should say \delta = 1 - \alpha. This can be seen by referencing eqn (8.40) on page 154 in the second edition of the book "A First Book of Quantum Theory", by Lahiri & Pal. Eqn (8.40) is
D_{\mu\nu}(k) = -\frac{1}{k^2 + i\epsilon}[g_{\mu\nu} - (1 - \xi)\frac{k_{\mu}k_{\nu}}{k^2}]
and is the photon propagator when the lagrangian is given by eqn (8.11) on page 148 together with eqn (8.26) on page 152 to get
\mathcal{L} = -\frac{1}{4}F_{\mu\nu}F^{\mu\nu} - \frac{1}{2\xi}(\partial_{\mu}A^{\mu})^2
which is the same as the eqn at the bottom of page 323 in Mandl & Shaw.
 
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I suppose you should give thanks to yourself!
 
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