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Mass breathed during diving

  1. Oct 12, 2013 #1
    1. The problem statement, all variables and given/known data

    Given: A scuba diver has a tank with an internal volume of 2500 cm^3 air tank which is pressurized to 22 MPa at 27 deg C. After diving for 20 minutes, she notices that the air pressure has reduced to 6 MPa while the temperature of the tank has dropped to 18 deg C.

    Find: What is the mass of air that the diver has breathed through her lungs during the dive?


    2. Relevant equations

    P2*V2/T2 = P1*V1/T1 or Pv=nRT ?

    3. The attempt at a solution

    I'm confused which equation we use to find the solution and from there on how to punch in all the numbers to get to the solution.

    I know the volume of air is 0.0883 m^3/Kmol, Rair = 0.2870 KJ/Kg*K, and mass = 28.97 kg/kmol
    Also R = 8.314 KJ/Kg*K
    I'm just really confused on where everything goes into play and why?
     
  2. jcsd
  3. Oct 12, 2013 #2

    rock.freak667

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    Homework Helper

    You should be able to use the first equation to get the volume of air left after 20 minutes. Once you get that volume then you can use PV=nRT or PV=mRairT
     
  4. Oct 12, 2013 #3
    When I found the volume it came out to be bigger than the original volume which doesn't feel right because I converted the cm^3 to m^3 and then switched to Kelvin for temp and the for the MPa conversion I did 10^3. Doing all this I came out with a volume that was 0.0088 m^3 roughly. Or is the volume supposed to be bigger?
     
  5. Oct 12, 2013 #4
    The first formula (general transformation of ideal gas) is obtained considering a process involving a fixed amount of gas.
    This is not what you have here.
     
  6. Oct 12, 2013 #5
    Would I go about it the way rock described but only using the second part PV=mRairT?
     
  7. Oct 12, 2013 #6
    The volume of air in the tank is unchanged.
    Find the mass before and after. And then the difference.
    The mass is related to number of moles by n=m/M where M is the molar mass.
     
  8. Oct 13, 2013 #7

    Borek

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    Staff: Mentor

    I would separately calculate n from PV=nRT for the number of moles at the beginning and at the end. That would tell me how many moles of the air mixture were spent. Then multiply by the average molar mass of air (which you can calculate knowing air composition).

    My bet is that the average molar mass of air is incorporated into Rair, but I never liked the idea of using separate R values for separate gases. It hides the generality of the ideal gas equation and Avogadro's hypothesis, leaving students confused.
     
  9. Oct 13, 2013 #8

    SteamKing

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    The universal R = 8.314 J/K*mol

    MW air = 28.97 g/mol

    Rair = (8.314 J/K*mol )/(0.02897 kg/mol) = 287 J/K*kg = 0.287 kJ/K*kg
     
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